Pembahasan Soal Buku Paket Matematika SMP Kelas 7 Halaman 55 (Kurikulum Merdeka)

Hai sobat semuanya, pada postingan kali ini mimin akan sajikan pembahasan beberapa soal buku paket matematika SMP kelas 7 halaman 55 (kurikulum merdeka). Selamat belajar. Semoga bermanfaat.

Soal nomor 1 (Perkalian)

Berikut ini catatan yang perlu diperhatikan pada operasi perkalian pada bilangan bulat.

$ \begin{aligned} (1).& (+2) × (+5)\\&=+(2 \times 5)\\ &= \color{red}{10}\\ \\ (2). & (+3) × (-8)\\ &= -(3 \times 8)\\&= \color{red}{-24}\\ \\ (3).& (-4) × (+9) \\&=-(4 \times 9)\\ &= \color{red}{-36}\\ \\ (4).& (-6) × (-7)\\&= +(6 \times 7)\\ &= \color{red}{42}\\ \\ (5).& 2 × (-6) × (+10)\\&= -(2 × 6 × 10)\\ &= \color{red}{-120}\\ \\ (6). &-3 × 8 × (-2)\\&=+(3 × 8 × 2)\\&= \color{red}{48}\\ \\ (7).&(-9)^2\\&= (-9) × (-9) \\ &= +(9 × 9)\\ &=\color{red}{81}\\ \\ (8).&-9^2\\&=-(9 × 9) \\&= \color{red}{-81}\\ \\ (9).&(-4)^3\\&= (-4) × (-4) × (-4) \\ &= -(4 × 4 × 4)\\ &=\color{red}{-64}\\ \\ (10).&0,7^2\\&= (0,7) × (0,7) \\ &= +(0,7 × 0,7)\\ &=\color{red}{0,49}\\ \\ (11).&  (-\frac{3}{5}) \times (+\frac{5}{8})\\&= -(\frac{3}{5} \times \frac{5}{8})\\&= \color{red}{-\frac{3}{8}}\\ \\ (12).& 8 \times (-\frac{1}{4}) \times (-7)\\&= +(8 \times \frac{1}{4} \times 7 )\\&=\color{red}{14}  \end{aligned}$

Soal nomor 2 (Pembagian)

Berikut ini catatan yang perlu diperhatikan pada operasi pembagian pada bilangan bulat.

$ \begin{aligned} (1).& (+12) : (+6)\\&=+(12 :6) \\&=\color{red}{2}\\ \\  (2).&(+10) : (-2)\\&=-(10 : 2)\\&= \color{red}{-5}\\ \\  (3). &(-18) : (+6)\\&= -(18 : 6)\\ &= \color{red}{-3}\\ \\  (4). &(-42) : (-7)\\&=+(42 : 7)\\ &= \color{red}{6}\\ \\ (5).&0 : (-3)\\&=\color{red}{0}\\ \\ (6).& (+3,2) : (-8)\\&=-(3,2:8)\\&=\color{red}{-0,4}\\ \\ (7).& (-\frac{2}{3}):6\\&=-(\frac{2}{3} \times \frac{1}{6})\\&=\color{red}{-\frac{1}{9}}\\ \\ (8). & (-12):(-\frac{4}{7})\\&=+(12 \times \frac{7}{4})\\&= \color{red}{21}\\ \\ (9). & \frac{5}{8}:(-\frac{3}{4})\\&= -(\frac{5}{8} \times \frac{4}{3} )\\&= \color{red}{-\frac{5}{6}}  \end{aligned}$

Soal nomor 3 (Hitungan dengan Operasi Perkalian dan Pembagian)

Berikut ini catatan yang perlu diperhatikan pada hitungan dengan operasi perkalian dan pembagian.

$ \begin{aligned} (1).&(-4) : (-2) × 7 \\&= (-4) \times (-\frac{1}{2}) × 7 \\&= +(4 \times \frac{1}{2} \times 7 )\\&= \color{red}{14}\\ \\ (2).& 20 × (-3) : (-5)\\&= 20 × (-3) \times (-\frac{1}{5})\\&= +(20 \times 3 \times \frac{1}{5}) \\&=\color{red}{12}\\ \\ (3).&6 : (-9) × 15\\&= 6 \times (-\frac{1}{9}) × 15 \\ &= -(6\times \frac{1}{9} × 15 )\\&= - \color{red}{10}\\ \\ (4).&(-3) × 6 : (-12)\\&=  (-3) × 6 \times (-\frac{1}{12})\\&= +(3 \times 6 \times \frac{1}{12})\\&= \color{red}{\frac{3}{2}} \\ \\ (5).& (-48) : (-8) : (-4)\\&= (-48) \times (-\frac{1}{8}) \times (-\frac{1}{4})\\&=-(48 \times \frac{1}{8} \times \frac{1}{4})\\&=\color{red}{ -\frac{3}{2}}\\ \\ (6).&\frac{2}{3} : (-\frac{9}{4}) \times 4\\&= \frac{2}{3} \times (-\frac{4}{9}) \times 4\\&= -(\frac{2}{3} \times \frac{4}{9} \times 4)\\&=-\color{red}{\frac{32}{27}}\\  \end{aligned}$

Soal nomor 4 (Hitungan dengan Kombinasi Empat Operasi)

$ \begin{aligned} (1).& (-4) + 2 × (-3)\\&=(-4) +  (-6)\\ &= \color{red}{-10}\\  \\ (2).& -8 – 6 × 3\\&= -8 – 18\\&= \color{red}{-26}\\ \\ (3).& 18 – 72 : (-9)\\&= 18 – 72 \times (-\frac{1}{9})\\&= 18+8\\&=\color{red}{26}\\ \\ (4).& 3 × (-12)\\&= \color{red}{-36}\\ \\ (5).&(5 - 19) : (-2)\\&= (-14) : (-2)\\&=(-14) \times (-\frac{1}{2})\\&=+(14 \times \frac{1}{2})\\&=\color{red}{7}\\ \\ (6).& 4 × (-2) + (-14) : 2\\&= 4 × (-2) + (-14) \times \frac{1}{2}\\&= (-8) + (-7) \\&= \color{red}{-15}\\ \\ (7).&36 :(-2)^2\\&= 36 :4 \\&=\color{red}{9}\\ \\ (8).&10-4^2\\&= 10-16\\&= \color{red}{-6}\\ \\ (9).&(-5)^2+(-5^2)\\&=25+(-25)\\&=\color{red}{0}\\ \\ (10). & (-45) : 3^2 + 15\\&= (-45) : 9 + 15\\&= (-45) \times \frac{1}{9} + 15\\&=(-5) + 15\\&= \color{red}{10}\\ \\ (11). &20+6 \times (7-10)\\ &= 20+6 \times (-3)\\&=20 +(-18)\\ &=\color{red}{2}\\ \\ (12).& 12-7 \times {8+(-9)}\\ &= 12-7 \times (-1)\\ &= 12+7\\ &= \color{red}{19}\\ \\ (13).&\frac{3}{4} + (-\frac{2}{3}) :2\\ &= \frac{3}{4} + (-\frac{2}{3}) \times \frac{1}{2}\\ &= \frac{3}{4} + (-\frac{1}{3})\\ &= \frac{9}{12} + (-\frac{4}{12})\\ &=\color{red}{\frac{5}{12}}\\ \\ (14).& \frac{7}{9}-(-\frac{1}{3})^2\\&=\frac{7}{9}-\frac{1}{9}\\&= \frac{6}{9}\\&=\color{red}{\frac{2}{3}} \end{aligned}$

Demikianlah pembahasan beberapa soal buku paket matematika SMP kelas 7 halaman 55 (kurikulum merdeka). Semoga bermanfaat. 

Referensi

Tim Gakko Tosho. 2021. Matematika untuk Sekolah Menengah Pertama Kelas VII. Jakarta: Kementerian Pendidikan, Kebudayaan, Riset, dan Teknologi.