Pembahasan Soal Buku Paket/BSE Matematika SMP Kelas 8 Halaman 15 (Kurikulum Merdeka)

Berikut ini mimin sajikan pembahasan beberapa soal Buku Paket/BSE matematika SMP kelas 8 halaman 15 (kurikulum merdeka). Selamat membaca, sobat. Semoga bermanfaat.

Soal nomor 1

Jawab:

\begin{aligned} (1) . & 2 x + 3 y + 7 x + 5 y \\ = 2 x + 7 x + 3 y + 5 y \\ = (2 + 7) x + (3 + 5) y \\ = 9 x + 8 y \\ (2) . & - 4 a + 8 b - 2 a - 5 b \\ = - 4 a - 2 a + 8 b - 5 b \\ = (- 4 - 2) a + (8 - 5) b \\ = - 6 a + 3 b \\ (3) . & 5 a^{2} + a^{2} \\ = (5 + 1) a^{2} \\ = 6 a^{2} \\ (4) . & 3 x^{2} - 6 x + 1 - 2 x^{2} + 4 x \\ = 3 x^{2} - 2 x^{2} - 6 x + 4 x + 1 \\ = (3 - 2) x^{2} + (- 6 + 4) x + 1 \\ = x^{2} - 2 x + 1 \\ (5) . & (7 a + b) + (- 9 a + 8 b) \\ = 7 a + b - 9 a + 8 b \\ = 7 a - 9 a + b + 8 b \\ = (7 - 9) a + (1 + 8) b \\ = - 2 a + 9 b \\ (6) . & (- 3 x^{2} - 4 x) + (5 x^{2} - x) \\ = - 3 x^{2} - 4 x + 5 x^{2} - x \\ = - 3 x^{2} + 5 x^{2} - 4 x - x \\ = (- 3 + 5) x^{2} + (- 4 - 1) x \\ = 2 x^{2} - 5 x \\ (7) . & (8 x - 6 y) - (2 x + 4 y) \\ = 8 x - 6 y - 2 x - 4 y \\ = 8 x - 2 x - 6 y - 4 y \\ = (8 - 2) x + (- 6 - 4) y \\ = 6 x - 10 y \\ (8) . & (- x^{2} + 9 x + 6) - (7 x^{2} - 5 x + 8) \\ = - x^{2} + 9 x + 6 - 7 x^{2} + 5 x - 8 \\ = - x^{2} - 7 x^{2} + 9 x + 5 x + 6 - 8 \\ = (- 1 - 7) x^{2} + (9 + 5) x - 2 \\ = - 8 x^{2} + 14 x - 2 \\ (9) . & 2 x - 6 y - 5 + 3 x + 2 y - 4 \\ = 2 x + 3 x - 6 y + 2 y - 5 - 4 \\ = (2 + 3) x + (- 6 + 2) y - 9 \\ = 5 x - 4 y - 9 \\ (10) . & (- 5 x + 8 y) - (4 x - 7 y) \\ = - 5 x + 8 y - 4 x + 7 y \\ = - 5 x - 4 x + 8 y + 7 y \\ = (- 5 - 4) x + (8 + 7) y \\ = - 9 x + 15 y \end{aligned}

Soal nomor 2

Jawab:

\begin{aligned} (1) . & 2 (6 a - 5 b + 1) \\ = 12 a - 10 b + 2 \\ (2) . & (9 x - 4 y) \times (- 3) \\ = - 27 x + 12 y \\ (3) . & (20 a + 16 b) : 4 \\ = (20 a + 16 b) \times \frac{1}{4} \\ = 5 a + 4 b \\ (4) . & \frac{8 x + 12 y}{- 2} \\ = \frac{8 x}{- 2} + \frac{12 y}{- 2} \\ = - 4 x - 6 y \end{aligned}

Soal nomor 3

Baca Juga

Pembahasan Soal Buku Paket/BSE Matematika SMP Kelas 8 Halaman 22 (Kurikulum Merdeka)
Pembahasan Soal Buku Paket/BSE Matematika SMP Kelas 8 Halaman 14 (Kurikulum Merdeka)
Pembahasan Soal Buku Paket/BSE Matematika SMP Kelas 8 Halaman 164 (Kurikulum Merdeka)

Jawab:

\begin{aligned} (1) . & 3 (a + 2 b) + 6 (a - b) \\ = 3 a + 6 a + 6 b - 6 b \\ = (3 + 6) a + (6 - 6) b \\ = 9 a \\ (2) . & - (5 x - y) + 4 (3 x - y) \\ = - 5 x + y + 12 x - 4 y \\ = - 5 x + 12 x + y - 4 y \\ = (- 5 + 12) x + (1 - 4) y \\ = 7 x - 3 y \\ (3) . & 2 (4 x + y) - 7 x \\ = 8 x + 2 y - 7 x \\ = 8 x - 7 x + 2 y \\ = (8 - 7) x + 2 y \\ = x + 2 y \\ (4) . & 8 a - 5 b - 3 (a - 4 b) \\ = 8 a - 5 b - 3 a + 12 b \\ = 8 a - 3 a - 5 b + 12 b \\ = (8 - 3) a + (- 5 + 12) b \\ = 5 a + 7 b \\ (5) . & 4 (2 x - y) - 2 (x - y + 1) \\ = 8 x - 4 y - 2 x + 2 y - 2 \\ = 8 x - 2 x - 4 y + 2 y - 2 \\ = (8 - 2) x + (- 4 + 2) y - 2 \\ = 6 x - 2 y - 2 \\ (6) . & \frac{1}{4} (a - 3 b) - \frac{1}{6} (2 a - 3 b) \\ = \frac{1}{4} a - \frac{3}{4} b - \frac{2}{6} a + \frac{3}{6} b \\ = \frac{- a - 3 b}{12} \\ (7) . & \frac{2 a - b}{6} + \frac{a + b}{8} \\ = \frac{8 (2 a - b) + 6 (a + b)}{48} \\ = \frac{16 a - 8 b + 6 a + 6 b}{48} \\ = \frac{22 a - 2 b}{48} \\ = \frac{11 a - b}{24} \\ (8) . & \frac{4 x - y}{3} - \frac{x - 3 y}{2} \\ = \frac{2 (4 x - y) - 3 (x - 3 y)}{6} \\ = \frac{8 x - 2 y - 3 x + 9 y}{6} \\ = \frac{5 x + 7 y}{6} \\ (9) . & x - \frac{x + 5 y}{2} \\ = \frac{2 x}{2} - \frac{x + 5 y}{2} \\ = \frac{2 x - x - 5 y}{2} \\ = \frac{x - 5 y}{2} \end{aligned}

Soal nomor 4

Jawab:

\begin{aligned} (1) . & 9 a \times (- 5 b) \\ = 9 \times a \times (- 5) \times b \\ = - 45 a b \\ (2) . & 12 x \times \frac{5}{6} y \\ = 12 \times x \times \frac{5}{6} \times y \\ = 10 x y \\ (3) . & 3 x^{2} \times 7 x \\ = 3 \times x \times x \times 7 \times x \\ = 21 x^{3} \\ (4) . & (- 7 a)^{2} \\ = (- 7 a) \times (- 7 a) \\ = - 7 \times a \times - 7 \times a \\ = 49 a^{2} \\ (5) . & 4 a \times (- a b) \\ = 4 \times a \times - a \times b \\ = - 4 a^{2} b \\ (6) . & (- 18 x y) : (- 9 x) \\ = (- 18 x y) \times - \frac{1}{9 x} \\ = - 18 \times x \times y \times - \frac{1}{9 x} \\ = 2 y \\ (7) . & x^{3} : x \\ = x^{3} \times \frac{1}{x} \\ = x \times x \times x \times \frac{1}{x} \\ = x^{2} \\ (8) . & 6 x^{2} : \frac{3}{4} x \\ = 6 x^{2} \times \frac{4}{3 x} \\ = 6 \times x \times x \times \frac{4}{3 x} \\ = 8 x \\ (9) . & x^{2} \times 4 x : 8 x y \\ = x^{2} \times 4 x \times \frac{1}{8 x y} \\ = \frac{x^{2}}{2 y} \\ (10) . & 15 a^{2} b : (- 6 a b^{2}) \times 2 a b \\ = 15 a^{2} b \times - \frac{1}{6 a b^{2}} \times 2 a b \\ = - 5 a^{2} \end{aligned}

Soal nomor 5

Jawab:

\begin{aligned} (1) . & a^{2} - b \\ = (- 3)^{2} - 8 \\ = 9 - 8 \\ = 1 \\ (2) . & 8 x^{2} y^{3} : 4 x y^{2} \\ = 8 x^{2} y^{3} \times \frac{1}{4 x y^{2}} \\ = 2 x y \\ = 2 \times 2 \times (- 5) \\ = - 20 \\ (3) . & (3 a + b) - (a + 4 b) \\ = 3 a + b - a - 4 b \\ = 2 a - 3 b \\ = 2 \times \frac{1}{2} - 3 \times (- 1) \\ = 1 + 3 \\ = 4 \end{aligned}

Demikianlah pembahasan beberapa soal Buku Paket/BSE matematika SMP kelas 8 halaman 15 (kurikulum merdeka). Semoga bermanfaat.

Referensi

Tim Gakko Tosho. 2021. Matematika untuk Sekolah Menengah Pertama Kelas VIII . Jakarta: Kementerian Pendidikan, Kebudayaan, Riset, dan Teknologi.